L'Hospital's Rule is a method for finding the value of a function using derivatives. This method is use when, the value at a point don't exist.
Suppose there are continuous function f(x) and g(x) that are both zero at x=a. Then, the limit cannot be found by substituting x=a since it give 0/0 which cannot be evaluated we use 0/0 as a notation for an expression known as an indeterminate form may be evaluated by cancellation or rearrangement of terms. However, this does not always work.
For example, how would you evaluate ? Obviously inserting x=0 will give an indeterminate form of 0/0 and, in this case you can neither use algebraic manipulation nor rearrangement of terms to reduce this expression into a form that yield a valid limit.
Statement: If f and g are differentiable function such that
1. or
Suppose there are continuous function f(x) and g(x) that are both zero at x=a. Then, the limit cannot be found by substituting x=a since it give 0/0 which cannot be evaluated we use 0/0 as a notation for an expression known as an indeterminate form may be evaluated by cancellation or rearrangement of terms. However, this does not always work.
For example, how would you evaluate ? Obviously inserting x=0 will give an indeterminate form of 0/0 and, in this case you can neither use algebraic manipulation nor rearrangement of terms to reduce this expression into a form that yield a valid limit.
L'Hospital's Rule
Statement: If f and g are differentiable function such that
1. or
2. f'(x), g'(x) both exist and
g'(x)≠0 ∀ x∈(a-δ,a+δ), δ>0 except possibly at x=a;
3. exist
Then
Examples
Q1. Evaluate the limit : .
Ans.
Directly applying x=0 leads the limit to an indeterminate form. Since both the term in the numerator and the term in the denominator are zero at x=0 and since sin x and x are both differentiable at x=0, we can use L'Hospital's Rule.
.
Q2. Evaluate
Ans.
Directly applying x=0 leads the limit to an indeterminate form. Since both the term in the numerator and the term in the denominator are zero at x=0 and since both are differentiable at x=0, we can use L'Hospital's Rule.
= 1.
Q3. Evaluate .
Ans.
Directly applying x=0 leads the limit to an indeterminate form. Since both the term in the numerator and the term in the denominator are zero at x=0 and since both are differentiable at x=0, we can use L'Hospital's Rule.
=
Since after applying L'Hospital's Rule we are getting 0/0 form. So we apply the rule again till we didn't get 0/0 form.
= 120×0
= 0
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